Expressions in α and β
α और β के व्यंजक
Lesson language · भाषा
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In this lesson
Summary
- The idea
- $\alpha^2+\beta^2=(\alpha+\beta)^2-2\alpha\beta$
- More expressions
- $\dfrac{1}{\alpha}+\dfrac{1}{\beta}=\dfrac{\alpha+\beta}{\alpha\beta}$
- Example 1
- $\alpha^2+\beta^2=13$ ✓
- Example 2
- $x^2-\dfrac{4}{3}x+\dfrac{1}{3}=0$ or $3x^2-4x+1=0$ ✓
- Careful
- First, remember the formulas.
- Your turn
- $\dfrac{1}{\alpha}+\dfrac{1}{\beta}=\dfrac{7}{5}$ ✓
हिन्दी में सारांश
- मूल विचार
- $\alpha^2+\beta^2=(\alpha+\beta)^2-2\alpha\beta$
- और व्यंजक
- $\dfrac{1}{\alpha}+\dfrac{1}{\beta}=\dfrac{\alpha+\beta}{\alpha\beta}$
- उदाहरण 1
- $\alpha^2+\beta^2=13$ ✓
- उदाहरण 2
- $x^2-\dfrac{4}{3}x+\dfrac{1}{3}=0$ या $3x^2-4x+1=0$ ✓
- सावधान
- पहली, सूत्र याद रखिए।
- अब आपकी बारी
- $\dfrac{1}{\alpha}+\dfrac{1}{\beta}=\dfrac{7}{5}$ ✓
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